geometry problems from Team Selection Tests (TST) from Georgia with aops links in the names
2005
In triangle ABC we have \angle{ACB} = 2\angle{ABC} and there exists the point D inside the triangle such that AD = AC and DB = DC. Prove that \angle{BAC} = 3\angle{BAD}.
Let ABCD be a convex quadrilateral. Points P,Q and R are the feets of the perpendiculars from point D to lines BC, CA and AB, respectively. Prove that PQ=QR if and only if the bisectors of the angles ABC and ADC meet on segment AC.
In a convex quadrilateral ABCD the points P and Q are chosen on the sides BC and CD respectively so that \angle{BAP}=\angle{DAQ}. Prove that the line, passing through the orthocenters of triangles ABP and ADQ, is perpendicular to AC if and only if the triangles ABP and ADQ have the same areas.
On the sides AB, BC, CD and DA of the rhombus ABCD, respectively, are chosen points E, F, G and H so, that EF and GH touch the incircle of the rhombus. Prove that the lines EH and FG are parallel.
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