geometry problems from the Second Round of Polish Mathematical Olympiads
with aops links in the names
Polska Olimpiada Matematyczna
1993 Polish 2nd Round P2
Let ABCD be a cyclic quadrilateral and let E and F be the points on the sides AB and CD respectively such that AE : EB = CF : FD. Point P on the segment EF satsfies EP : PF = AB : CD. Prove that the ratio of the areas of \vartriangle APD and \vartriangle BPC does not depend on the choice of E and F.
Bisector of angle BAC of triangle ABC intersects circumcircle of this triangle in point D \neq A. Points K and L are orthogonal projections on line AD of points B and C, respectively. Prove that AD \ge BK + CL.
2000 Polish 2nd Round P4
Point I is incenter of triangle ABC in which AB \neq AC. Lines BI and CI intersect sides AC and AB in points D and E, respectively. Determine all measures of angle BAC, for which may be DI = EI.
2001 Polish 2nd Round P2
Points A,B,C with AB<BC lie in this order on a line. Let ABDE be a square. The circle with diameter AC intersects the line DE at points P and Q with P between D and E. The lines AQ and BD intersect at R. Prove that DP=DR.
2001 Polish 2nd Round P5
In a triangle ABC, I is the incentre and D the intersection point of AI and BC. Show that AI+CD=AC if and only if \angle B=60^{\circ}+\frac{_1}{^3}\angle C.
2002 Polish 2nd Round P2
In a convex quadrilateral ABCD, both \angle ADB=2\angle ACB and \angle BDC=2\angle BAC. Prove that AD=CD.
2002 Polish 2nd Round P5
Triangle ABC with \angle BAC=90^{\circ} is the base of the pyramid ABCD. Moreover, AD=BD and AB=CD. Prove that \angle ACD\ge 30^{\circ}.
2003 Polish 2nd Round P2
The quadrilateral ABCD is inscribed in the circle o. Bisectors of angles DAB and ABC intersect at point P, and bisectors of angles BCD and CDA intersect in point Q. Point M is the center of this arc BC of the circle o which does not contain points D and A. Point N is the center of the arc DA of the circle o, which does not contain points B and C. Prove that the points P and Q lie on the line perpendicular to MN.
2003 Polish 2nd Round P5
Point A lies outside circle o of center O. From point A draw two lines tangent to a circle o in points B and C. A tangent to a circle o cuts segments AB and AC in points E and F, respectively. Lines OE and OF cut segment BC in points P and Q, respectively. Prove that from line segments BP, PQ, QC can construct triangle similar to triangle AEF.
2004 Polish 2nd Round P2
In convex hexagon ABCDEF all sides have equal length and \angle A+\angle C+\angle E=\angle B+\angle D+\angle F. Prove that the diagonals AD,BE,CF are concurrent.
2004 Polish 2nd Round P5
Points D and E are taken on sides BC and CA of a triangle BD=AE. Segments AD and BE meet at P. The bisector of \angle ACB intersects AD and BE at Q and R respectively. Prove that \frac{PQ}{PR}=\frac{AD}{BE}.
2005 Polish 2nd Round P2
In a convex quadrilateral ABCD, point M is the midpoint of the diagonal AC. Prove that if \angle BAD=\angle BMC=\angle CMD, then a circle can be inscribed in quadrilateral ABCD.
2005 Polish 2nd Round P5
A rhombus ABCD with \angle BAD=60^{\circ} is given. Points E on side AB and F on side AD are such that \angle ECF=\angle ABD. Lines CE and CF respectively meet line BD at P and Q. Prove that \frac{PQ}{EF}=\frac{AB}{BD}.
2006 Polish 2nd Round P2 (IMO ISL 2005)
Given a triangle ABC satisfying AC+BC=3\cdot AB. The incircle of triangle ABC has center I and touches the sides BC and CA at the points D and E, respectively. Let K and L be the reflections of the points D and E with respect to I. Prove that the points A, B, K, L lie on one circle.
Point C is a midpoint of AB. Circle o_1 which passes through A and C intersect circle o_2 which passes through B and C in two different points C and D. Point P is a midpoint of arc AD of circle o_1 which doesn't contain C. Point Q is a midpoint of arc BD of circle o_2 which doesn't contain C. Prove that PQ \perp CD.
2007 Polish 2nd Round P2
ABCDE is a convex pentagon and BC=CD, \;\;\; DE=EA, \;\;\; \angle BCD=\angle DEA=90^{\circ}
Prove, that it is possible to build a triangle from segments AC, CE, EB. Find the value of its angles if \angle ACE=\alpha and \angle BEC=\beta.
2007 Polish 2nd Round P5
We are given a cyclic quadrilateral ABCD \quad AB\not=CD. Quadrilaterals AKDL and CMBN are rhombuses with equal sides. Prove, that KLMN is cyclic
2008 Polish 2nd Round P2
In the convex pentagon ABCDE following equalities holds: \angle ABD= \angle ACE, \angle ACB=\angle ACD, \angle ADC=\angle ADE and \angle ADB=\angle AEC. The point S is the intersection of the segments BD and CE. Prove that lines AS and CD are perpendicular.
2008 Polish 2nd Round P5
We are given a triangle ABC such that AC = BC. There is a point D lying on the segment AB, and AD < DB. The point E is symmetrical to A with respect to CD. Prove that: \frac {AC}{CD} = \frac {BE}{BD - AD}
2009 Polish 2nd Round P3
Disjoint circles o_1, o_2, with centers I_1, I_2 respectively, are tangent to the line k at A_1, A_2 respectively and they lie on the same side of this line. Point C lies on segment I_1I_2 and \angle A_1CA_2 = 90^{\circ}. Let B_1 be the second intersection of A_1C with o_1, and let B_2 be the second intersection of A_2C with o_2. Prove that B_1B_2 is tangent to the circles o_1, o_2.
2009 Polish 2nd Round P4
ABCD is a cyclic quadrilateral inscribed in the circle \Gamma with AB as diameter. Let E be the intersection of the diagonals AC and BD. The tangents to \Gamma at the points C,D meet at P. Prove that PC=PE.
2010 Polish 2nd Round P2
The orthogonal projections of the vertices A, B, C of the tetrahedron ABCD on the opposite faces are denoted by A', B', C' respectively. Suppose that point A' is the circumcenter of the triangle BCD, point B' is the incenter of the triangle ACD and C' is the centroid of the triangle ABD. Prove that tetrahedron ABCD is regular.
2010 Polish 2nd Round P4
In the convex pentagon ABCDE all interior angles have the same measure. Prove that the perpendicular bisector of segment EA, the perpendicular bisector of segment BC and the angle bisector of \angle CDE intersect in one point.
2011 Polish 2nd Round P2
The convex quadrilateral ABCD is given, AB<BC and AD<CD. P,Q are points on BC and CD respectively such that PB=AB and QD=AD. M is midpoint of PQ. We assume that \angle BMD=90^{\circ}, prove that ABCD is cyclic.
2011 Polish 2nd Round P4
Points A,B,C,D,E,F lie in that order on semicircle centered at O, we assume that AD=BE=CF. G is a common point of BE and AD, H is a common point of BE and CD. Prove that: \angle AOC=2\angle GOH.
2012 Polish 2nd Round P2
Prove that for tetrahedron ABCD; vertex D, center of insphere and centroid of ABCD are collinear iff areas of triangles ABD,BCD,CAD are equal.
2012 Polish 2nd Round P5
Let ABC be a triangle with \angle A=60^{\circ} and AB\neq AC, I-incenter, O-circumcenter. Prove that perpendicular bisector of AI, line OI and line BC have a common point.
2013 Polish 2nd Round P2
Circles o_1 and o_2 with centers in O_1 and O_2, respectively, intersect in two different points A and B, wherein angle O_1AO_2 is obtuse. Line O_1B intersects circle o_2 in point C \neq B. Line O_2B intersects circle o_1 in point D \neq B. Show that point B is incenter of triangle ACD.
2013 Polish 2nd Round P6
Decide, whether exist tetrahedrons T, T' with walls S_1, S_2, S_3, S_4 and S_1', S_2', S_3', S_4', respectively, such that for i = 1, 2, 3, 4 triangle S_i is similar to triangle S_i', but despite this, tetrahedron T is not similar to tetrahedron T'.
2014 Polish 2nd Round P2
Distinct points A, B and C lie on a line in this order. Point D lies on the perpendicular bisector of the segment BC. Denote by M the midpoint of the segment BC. Let r be the radius of the incircle of the triangle ABD and let R be the radius of the circle with center lying outside the triangle ACD, tangent to CD, AC and AD. Prove that DM=r+R.
2014 Polish 2nd Round P5
Circles o_1 and o_2 tangent to some line at points A and B, respectively, intersect at points X and Y (X is closer to the line AB). Line AX intersects o_2 at point P\neq X. Tangent to o_2 at point P intersects line AB at point Q. Prove that \sphericalangle XYB = \sphericalangle BYQ.
2015 Polish 2nd Round P1
Points E, F, G lie, and on the sides BC, CA, AB, respectively of a triangle ABC, with 2AG=GB, 2BE=EC and 2CF=FA. Points P and Q lie on segments EG and FG, respectively such that 2EP = PG and 2GQ=QF. Prove that the quadrilateral AGPQ is a parallelogram.
2015 Polish 2nd Round P6
Let ABC be a triangle. Let K be a midpoint of BC and M be a point on the segment AB. L=KM \cap AC and C lies on the segment AC between A and L. Let N be a midpoint of ML. AN cuts circumcircle of \Delta ABC in S and S \neq N. Prove that circumcircle of \Delta KSN is tangent to BC.
2016 Polish 2nd Round P1
Point P lies inside triangle of sides of length 3, 4, 5. Show that if distances between P and vertices of triangle are rational numbers then distances from P to sides of triangle are rational numbers too.
2016 Polish 2nd Round P2
In acute triangle ABC bisector of angle BAC intersects side BC in point D. Bisector of line segment AD intersects circumcircle of triangle ABC in points E and F. Show that circumcircle of triangle DEF is tangent to line BC.
2016 Polish 2nd Round P5
Quadrilateral ABCD is inscribed in circle. Points P and Q lie respectively on rays AB^{\rightarrow} and AD^{\rightarrow} such that AP = CD, AQ = BC. Show that middle point of line segment PQ lies on the line AC.
2017 Polish 2nd Round P2
In an acute triangle ABC the bisector of \angle BAC crosses BC at D. Points P and Q are orthogonal projections of D on lines AB and AC. Prove that [APQ]=[BCQP] if and only if the circumcenter of ABC lies on PQ.
2017 Polish 2nd Round P4
Incircle of a triangle ABC touches AB and AC at D and E, respectively. Point J is the excenter of A. Points M and N are midpoints of JD and JE. Lines BM and CN cross at point P. Prove that P lies on the circumcircle of ABC.
2018 Polish 2nd Round P3
Bisector of side BC intersects circumcircle of triangle ABC in points P and Q. Points A and P lie on the same side of line BC. Point R is an orthogonal projection of point P on line AC. Point S is middle of line segment AQ. Show that points A, B, R, S lie on one circle.
2018 Polish 2nd Round P4
Let ABCD be a trapezoid with bases AB and CD. Circle of diameter BC is tangent to line AD. Prove, that circle of diameter AD is tangent to line BC.
2019 Polish 2nd Round P1
A cyclic quadrilateral ABCD is given. Point K_1, K_2 lie on the segment AB, points L_1, L_2 on the segment BC, points M_1, M_2 on the segment CD and points N_1, N_2 on the segment DA. Moreover, points K_1, K_2, L_1, L_2, M_1, M_2, N_1, N_2 lie on a circle \omega in that order. Denote by a, b, c, d the lengths of the arcs N_2K_1, K_2L_1, L_2M_1, M _2N_1 of the circle \omega not containing points K_2, L_2, M_2, N_2, respectively. Prove that a+c=b+d.
2019 Polish 2nd Round P6
Let X be a point lying in the interior of the acute triangle ABC such that \sphericalangle BAX = 2\sphericalangle XBA and \sphericalangle XAC = 2\sphericalangle ACX. Denote by M the midpoint of the arc BC of the circumcircle (ABC) containing A. Prove that XM=XA.
2020 Polish 2nd Round P3
Let M be the midpoint of the side BC of a acute triangle ABC. Incircle of the triangle ABM is tangent to the side AB at the point D. Incircle of the triangle ACM is tangent to the side AC at the point E. Let F be the such point, that the quadrilateral DMEF is a parallelogram. Prove that F lies on the bisector of \angle BAC.
2020 Polish 2nd Round P4
Let ABCDEF be a such convex hexagon that
AB=CD=EF\; \text{and} \; BC=DE=.FA Prove that if \sphericalangle FAB + \sphericalangle ABC=\sphericalangle FAB + \sphericalangle EFA = 240^{\circ}, then \sphericalangle FAB+\sphericalangle CDE=240^{\circ}.
with aops links in the names
Polska Olimpiada Matematyczna
1993 - 2021
1993 Polish 2nd Round P2
Let be given a circle with center O and a point P outside the circle. A line l passes through P and cuts the circle at A and B. Let C be the point symmetric to A with respect to OP, and let m be the line BC. Prove that all lines m have a common point as l varies.
1993 Polish 2nd Round P3
1999 Polish 2nd Round P31993 Polish 2nd Round P3
A tetrahedron OA_1B_1C_1 is given. Let A_2,A_3 \in OA_1, A_2,A_3 \in OA_1, A_2,A_3 \in OA_1 be points such that the planes A_1B_1C_1,A_2B_2C_2 and A_3B_3C_3 are parallel and OA_1 > OA_2 > OA_3 > 0. Let V_i be the volume of the tetrahedron OA_iB_iC_i (i = 1,2,3) and V be the volume of OA_1B_2C_3. Prove that V_1 +V_2 +V_3 \ge 3V.
Let D,E,F be points on the sides BC,CA,AB of a triangle ABC, respectively. Suppose that the inradii of the triangles AEF,BFD,CDE are all equal to r_1. If r_2 and r are the inradii of triangles DEF and ABC respectively, prove that r_1 +r_2 =r.
1994 Polish 2nd Round P3
A plane passing through the center of a cube intersects the cube in a cyclic hexagon. Show that this hexagon is regular.
The incircle \omega of a triangle ABC is tangent to the sides AB and BC at P and Q respectively. The angle bisector at A meets PQ at point S. Prove \angle ASC = 90^o
Let D,E,F be points on the sides BC,CA,AB of a triangle ABC, respectively. Suppose that the inradii of the triangles AEF,BFD,CDE are all equal to r_1. If r_2 and r are the inradii of triangles DEF and ABC respectively, prove that r_1 +r_2 =r.
1994 Polish 2nd Round P3
A plane passing through the center of a cube intersects the cube in a cyclic hexagon. Show that this hexagon is regular.
1995 Polish 2nd Round P2
Let ABCDEF be a convex hexagon with AB = BC, CD = DE and EF = FA.
Prove that the lines through C,E,A perpendicular to BD,DF,FB are concurrent.
Let ABCDEF be a convex hexagon with AB = BC, CD = DE and EF = FA.
Prove that the lines through C,E,A perpendicular to BD,DF,FB are concurrent.
1995 Polish 2nd Round P5
The incircles of the faces ABC and ABD of a tetrahedron ABCD are tangent to the edge AB in the same point. Prove that the points of tangency of these incircles to the edges AC,BC,AD,BD are concyclic.
The incircles of the faces ABC and ABD of a tetrahedron ABCD are tangent to the edge AB in the same point. Prove that the points of tangency of these incircles to the edges AC,BC,AD,BD are concyclic.
1996 Polish 2nd Round P2
A circle with center O inscribed in a convex quadrilateral ABCD is tangent to the lines AB, BC, CD, DA at points K, L, M, N respectively. Assume that the lines KL and MN are not parallel and intersect at the point S. Prove that BD is perpendicular OS.
A circle with center O inscribed in a convex quadrilateral ABCD is tangent to the lines AB, BC, CD, DA at points K, L, M, N respectively. Assume that the lines KL and MN are not parallel and intersect at the point S. Prove that BD is perpendicular OS.
1996 Polish 2nd Round P6
Prove that every interior point of a parallelepiped with edges a,b,c is on the distance at most \frac12 \sqrt{a^2 +b^2 +c^2} from some vertex of the parallelepiped.
Prove that every interior point of a parallelepiped with edges a,b,c is on the distance at most \frac12 \sqrt{a^2 +b^2 +c^2} from some vertex of the parallelepiped.
1997 Polish 2nd Round P2
Let P be a point inside triangle ABC such that 3<ABP = 3<ACP = <ABC + <ACB. Prove that AB/(AC + PB) = AC/(AB + PC).
Let P be a point inside triangle ABC such that 3<ABP = 3<ACP = <ABC + <ACB. Prove that AB/(AC + PB) = AC/(AB + PC).
1997 Polish 2nd Round P6
Let eight points be given in a unit cube. Prove that two of these points are on a distance not greater than 1.
1998 Polish 2nd Round P2
In triangle ABC, the angle \angle BCA is obtuse and \angle BAC = 2\angle ABC\,. The line through B and perpendicular to BC intersects line AC in D. Let M be the midpoint of AB. Prove that \angle AMC=\angle BMD.
Let eight points be given in a unit cube. Prove that two of these points are on a distance not greater than 1.
1998 Polish 2nd Round P2
In triangle ABC, the angle \angle BCA is obtuse and \angle BAC = 2\angle ABC\,. The line through B and perpendicular to BC intersects line AC in D. Let M be the midpoint of AB. Prove that \angle AMC=\angle BMD.
1998 Polish 2nd Round P6
Prove that the edges AB and CD of a tetrahedron ABCD are perpendicular if and only if there exists a parallelogram CDPQ such that PA = PB = PD and QA = QB = QC.
Prove that the edges AB and CD of a tetrahedron ABCD are perpendicular if and only if there exists a parallelogram CDPQ such that PA = PB = PD and QA = QB = QC.
Let ABCD be a cyclic quadrilateral and let E and F be the points on the sides AB and CD respectively such that AE : EB = CF : FD. Point P on the segment EF satsfies EP : PF = AB : CD. Prove that the ratio of the areas of \vartriangle APD and \vartriangle BPC does not depend on the choice of E and F.
1999 Polish 2nd Round P4
Let P be a point inside a triangle ABC such that \angle PAB = \angle PCA and \angle PAC = \angle PBA. If O \ne P is the circumcenter of \triangle ABC, prove that \angle APO is right.
2000 Polish 2nd Round P2Let P be a point inside a triangle ABC such that \angle PAB = \angle PCA and \angle PAC = \angle PBA. If O \ne P is the circumcenter of \triangle ABC, prove that \angle APO is right.
Bisector of angle BAC of triangle ABC intersects circumcircle of this triangle in point D \neq A. Points K and L are orthogonal projections on line AD of points B and C, respectively. Prove that AD \ge BK + CL.
2000 Polish 2nd Round P4
Point I is incenter of triangle ABC in which AB \neq AC. Lines BI and CI intersect sides AC and AB in points D and E, respectively. Determine all measures of angle BAC, for which may be DI = EI.
2001 Polish 2nd Round P2
Points A,B,C with AB<BC lie in this order on a line. Let ABDE be a square. The circle with diameter AC intersects the line DE at points P and Q with P between D and E. The lines AQ and BD intersect at R. Prove that DP=DR.
2001 Polish 2nd Round P5
In a triangle ABC, I is the incentre and D the intersection point of AI and BC. Show that AI+CD=AC if and only if \angle B=60^{\circ}+\frac{_1}{^3}\angle C.
2002 Polish 2nd Round P2
In a convex quadrilateral ABCD, both \angle ADB=2\angle ACB and \angle BDC=2\angle BAC. Prove that AD=CD.
2002 Polish 2nd Round P5
Triangle ABC with \angle BAC=90^{\circ} is the base of the pyramid ABCD. Moreover, AD=BD and AB=CD. Prove that \angle ACD\ge 30^{\circ}.
The quadrilateral ABCD is inscribed in the circle o. Bisectors of angles DAB and ABC intersect at point P, and bisectors of angles BCD and CDA intersect in point Q. Point M is the center of this arc BC of the circle o which does not contain points D and A. Point N is the center of the arc DA of the circle o, which does not contain points B and C. Prove that the points P and Q lie on the line perpendicular to MN.
2003 Polish 2nd Round P5
Point A lies outside circle o of center O. From point A draw two lines tangent to a circle o in points B and C. A tangent to a circle o cuts segments AB and AC in points E and F, respectively. Lines OE and OF cut segment BC in points P and Q, respectively. Prove that from line segments BP, PQ, QC can construct triangle similar to triangle AEF.
In convex hexagon ABCDEF all sides have equal length and \angle A+\angle C+\angle E=\angle B+\angle D+\angle F. Prove that the diagonals AD,BE,CF are concurrent.
2004 Polish 2nd Round P5
Points D and E are taken on sides BC and CA of a triangle BD=AE. Segments AD and BE meet at P. The bisector of \angle ACB intersects AD and BE at Q and R respectively. Prove that \frac{PQ}{PR}=\frac{AD}{BE}.
2005 Polish 2nd Round P2
In a convex quadrilateral ABCD, point M is the midpoint of the diagonal AC. Prove that if \angle BAD=\angle BMC=\angle CMD, then a circle can be inscribed in quadrilateral ABCD.
2005 Polish 2nd Round P5
A rhombus ABCD with \angle BAD=60^{\circ} is given. Points E on side AB and F on side AD are such that \angle ECF=\angle ABD. Lines CE and CF respectively meet line BD at P and Q. Prove that \frac{PQ}{EF}=\frac{AB}{BD}.
2006 Polish 2nd Round P2 (IMO ISL 2005)
Given a triangle ABC satisfying AC+BC=3\cdot AB. The incircle of triangle ABC has center I and touches the sides BC and CA at the points D and E, respectively. Let K and L be the reflections of the points D and E with respect to I. Prove that the points A, B, K, L lie on one circle.
by Dimitris Kontogiannis, Greec
2006 Polish 2nd Round P5Point C is a midpoint of AB. Circle o_1 which passes through A and C intersect circle o_2 which passes through B and C in two different points C and D. Point P is a midpoint of arc AD of circle o_1 which doesn't contain C. Point Q is a midpoint of arc BD of circle o_2 which doesn't contain C. Prove that PQ \perp CD.
2007 Polish 2nd Round P2
ABCDE is a convex pentagon and BC=CD, \;\;\; DE=EA, \;\;\; \angle BCD=\angle DEA=90^{\circ}
Prove, that it is possible to build a triangle from segments AC, CE, EB. Find the value of its angles if \angle ACE=\alpha and \angle BEC=\beta.
2007 Polish 2nd Round P5
We are given a cyclic quadrilateral ABCD \quad AB\not=CD. Quadrilaterals AKDL and CMBN are rhombuses with equal sides. Prove, that KLMN is cyclic
2008 Polish 2nd Round P2
In the convex pentagon ABCDE following equalities holds: \angle ABD= \angle ACE, \angle ACB=\angle ACD, \angle ADC=\angle ADE and \angle ADB=\angle AEC. The point S is the intersection of the segments BD and CE. Prove that lines AS and CD are perpendicular.
2008 Polish 2nd Round P5
We are given a triangle ABC such that AC = BC. There is a point D lying on the segment AB, and AD < DB. The point E is symmetrical to A with respect to CD. Prove that: \frac {AC}{CD} = \frac {BE}{BD - AD}
2009 Polish 2nd Round P3
Disjoint circles o_1, o_2, with centers I_1, I_2 respectively, are tangent to the line k at A_1, A_2 respectively and they lie on the same side of this line. Point C lies on segment I_1I_2 and \angle A_1CA_2 = 90^{\circ}. Let B_1 be the second intersection of A_1C with o_1, and let B_2 be the second intersection of A_2C with o_2. Prove that B_1B_2 is tangent to the circles o_1, o_2.
2009 Polish 2nd Round P4
ABCD is a cyclic quadrilateral inscribed in the circle \Gamma with AB as diameter. Let E be the intersection of the diagonals AC and BD. The tangents to \Gamma at the points C,D meet at P. Prove that PC=PE.
The orthogonal projections of the vertices A, B, C of the tetrahedron ABCD on the opposite faces are denoted by A', B', C' respectively. Suppose that point A' is the circumcenter of the triangle BCD, point B' is the incenter of the triangle ACD and C' is the centroid of the triangle ABD. Prove that tetrahedron ABCD is regular.
In the convex pentagon ABCDE all interior angles have the same measure. Prove that the perpendicular bisector of segment EA, the perpendicular bisector of segment BC and the angle bisector of \angle CDE intersect in one point.
2011 Polish 2nd Round P2
The convex quadrilateral ABCD is given, AB<BC and AD<CD. P,Q are points on BC and CD respectively such that PB=AB and QD=AD. M is midpoint of PQ. We assume that \angle BMD=90^{\circ}, prove that ABCD is cyclic.
2011 Polish 2nd Round P4
Points A,B,C,D,E,F lie in that order on semicircle centered at O, we assume that AD=BE=CF. G is a common point of BE and AD, H is a common point of BE and CD. Prove that: \angle AOC=2\angle GOH.
2012 Polish 2nd Round P2
Prove that for tetrahedron ABCD; vertex D, center of insphere and centroid of ABCD are collinear iff areas of triangles ABD,BCD,CAD are equal.
2012 Polish 2nd Round P5
Let ABC be a triangle with \angle A=60^{\circ} and AB\neq AC, I-incenter, O-circumcenter. Prove that perpendicular bisector of AI, line OI and line BC have a common point.
Circles o_1 and o_2 with centers in O_1 and O_2, respectively, intersect in two different points A and B, wherein angle O_1AO_2 is obtuse. Line O_1B intersects circle o_2 in point C \neq B. Line O_2B intersects circle o_1 in point D \neq B. Show that point B is incenter of triangle ACD.
2013 Polish 2nd Round P6
Decide, whether exist tetrahedrons T, T' with walls S_1, S_2, S_3, S_4 and S_1', S_2', S_3', S_4', respectively, such that for i = 1, 2, 3, 4 triangle S_i is similar to triangle S_i', but despite this, tetrahedron T is not similar to tetrahedron T'.
Distinct points A, B and C lie on a line in this order. Point D lies on the perpendicular bisector of the segment BC. Denote by M the midpoint of the segment BC. Let r be the radius of the incircle of the triangle ABD and let R be the radius of the circle with center lying outside the triangle ACD, tangent to CD, AC and AD. Prove that DM=r+R.
2014 Polish 2nd Round P5
Circles o_1 and o_2 tangent to some line at points A and B, respectively, intersect at points X and Y (X is closer to the line AB). Line AX intersects o_2 at point P\neq X. Tangent to o_2 at point P intersects line AB at point Q. Prove that \sphericalangle XYB = \sphericalangle BYQ.
2015 Polish 2nd Round P1
Points E, F, G lie, and on the sides BC, CA, AB, respectively of a triangle ABC, with 2AG=GB, 2BE=EC and 2CF=FA. Points P and Q lie on segments EG and FG, respectively such that 2EP = PG and 2GQ=QF. Prove that the quadrilateral AGPQ is a parallelogram.
2015 Polish 2nd Round P6
Let ABC be a triangle. Let K be a midpoint of BC and M be a point on the segment AB. L=KM \cap AC and C lies on the segment AC between A and L. Let N be a midpoint of ML. AN cuts circumcircle of \Delta ABC in S and S \neq N. Prove that circumcircle of \Delta KSN is tangent to BC.
2016 Polish 2nd Round P1
Point P lies inside triangle of sides of length 3, 4, 5. Show that if distances between P and vertices of triangle are rational numbers then distances from P to sides of triangle are rational numbers too.
2016 Polish 2nd Round P2
In acute triangle ABC bisector of angle BAC intersects side BC in point D. Bisector of line segment AD intersects circumcircle of triangle ABC in points E and F. Show that circumcircle of triangle DEF is tangent to line BC.
2016 Polish 2nd Round P5
Quadrilateral ABCD is inscribed in circle. Points P and Q lie respectively on rays AB^{\rightarrow} and AD^{\rightarrow} such that AP = CD, AQ = BC. Show that middle point of line segment PQ lies on the line AC.
In an acute triangle ABC the bisector of \angle BAC crosses BC at D. Points P and Q are orthogonal projections of D on lines AB and AC. Prove that [APQ]=[BCQP] if and only if the circumcenter of ABC lies on PQ.
2017 Polish 2nd Round P4
Incircle of a triangle ABC touches AB and AC at D and E, respectively. Point J is the excenter of A. Points M and N are midpoints of JD and JE. Lines BM and CN cross at point P. Prove that P lies on the circumcircle of ABC.
2018 Polish 2nd Round P3
Bisector of side BC intersects circumcircle of triangle ABC in points P and Q. Points A and P lie on the same side of line BC. Point R is an orthogonal projection of point P on line AC. Point S is middle of line segment AQ. Show that points A, B, R, S lie on one circle.
2018 Polish 2nd Round P4
Let ABCD be a trapezoid with bases AB and CD. Circle of diameter BC is tangent to line AD. Prove, that circle of diameter AD is tangent to line BC.
A cyclic quadrilateral ABCD is given. Point K_1, K_2 lie on the segment AB, points L_1, L_2 on the segment BC, points M_1, M_2 on the segment CD and points N_1, N_2 on the segment DA. Moreover, points K_1, K_2, L_1, L_2, M_1, M_2, N_1, N_2 lie on a circle \omega in that order. Denote by a, b, c, d the lengths of the arcs N_2K_1, K_2L_1, L_2M_1, M _2N_1 of the circle \omega not containing points K_2, L_2, M_2, N_2, respectively. Prove that a+c=b+d.
2019 Polish 2nd Round P6
Let X be a point lying in the interior of the acute triangle ABC such that \sphericalangle BAX = 2\sphericalangle XBA and \sphericalangle XAC = 2\sphericalangle ACX. Denote by M the midpoint of the arc BC of the circumcircle (ABC) containing A. Prove that XM=XA.
2020 Polish 2nd Round P3
Let M be the midpoint of the side BC of a acute triangle ABC. Incircle of the triangle ABM is tangent to the side AB at the point D. Incircle of the triangle ACM is tangent to the side AC at the point E. Let F be the such point, that the quadrilateral DMEF is a parallelogram. Prove that F lies on the bisector of \angle BAC.
2020 Polish 2nd Round P4
Let ABCDEF be a such convex hexagon that
AB=CD=EF\; \text{and} \; BC=DE=.FA Prove that if \sphericalangle FAB + \sphericalangle ABC=\sphericalangle FAB + \sphericalangle EFA = 240^{\circ}, then \sphericalangle FAB+\sphericalangle CDE=240^{\circ}.
The point P lies on the side CD of the parallelogram ABCD with \angle DBA = \angle CBP. Point O is the center of the circle passing through the points D and P and tangent to the straight line AD at point D. Prove that AO = OC.
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