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Metropolises 2016-21 (IOM) (Russia) 10p

geometry problems from International Olympiad of Metropolises (IOM)
with aops links in the names



collected inside aops here


2016 - 2021

Let A1A2 . . .An be a cyclic convex polygon whose circumcenter is strictly in its interior. Let B1, B2, …, Bn be arbitrary points on the sides A1A2, A2A3, …, AnA1, respectively, other than the vertices. Prove that \frac{{{B}_{1}}{{B}_{2}}}{{{A}_{1}}{{A}_{3}}}+\frac{{{B}_{2}}{{B}_{3}}}{{{A}_{2}}{{A}_{4}}}+...+\frac{{{B}_{n}}{{B}_{1}}}{{{A}_{n}}{{A}_{1}}}>1

A convex quadrilateral ABCD has right angles at A and  C. A point E lies on the extension of the side AD beyond D so that < ABE = < ADC. The point K is symmetric to the point C with respect to point A. Prove that < ADB = < AKE.

Let ABCD be a parallelogram in which the angle at B is obtuse and AD > AB. Points K and L are chosen on the diagonal AC such that < ABK = < ADL (the points A, K, L, C are all different, with K between A and L). The line BK intersects the circumcircle ω of triangle ABC at points B and E, and the line EL intersects ω at points E and F. Prove that BF // AC.

Let ABCDEF be a convex hexagon which has an inscribed circle and a circumscribed circle. Denote by ωA, ωB, ωC, ωD, ωE, and ωF the inscribed circles of the triangles FAB, ABC, BCD, CDE, DEF, and EFA, respectively. Let lAB be the external common  tangent of ωA and ωB other than the line AB; lines lBC, lCD, lDE, lEF , and lFA are analogously defined. Let A1 be the intersection point of the lines lFA and lAB , B1 be the intersection point of the lines lAB and lBC , points C1, D1, E1, and F1 are analogously defined. Suppose that A1B1C1D1E1F1 is a convex hexagon. Show that its diagonals A1D1, B1E1, and C1F1 meet at a single point.

A convex quadrilateral ABCD is circumscribed about a circle \omega. Let PQ be the diameter of \omega perpendicular to AC. Suppose lines BP and DQ intersect at point X, and lines BQ and DP intersect at point Y. Show that the points X and Y lie on the line AC.

 Géza Kós
The incircle of a triangle ABC touches the sides BC and AC at points D and E, respectively. Suppose P is the point on the shorter arc DE of the incircle such that \angle APE = \angle DPB. The segments AP and BP meet the segment DE at points K and L, respectively. Prove that 2KL = DE.

Dušan Djukić
In a non-equilateral triangle ABC point I is the incenter and point O is the circumcenter. A line s through I is perpendicular to IO. Line \ell symmetric to like BC with respect to s meets the segments AB and AC at points K and L, respectively (K and L are different from A). Prove that the circumcenter of triangles AKL lies on the line IO.

We are given a convex four-sided pyramid with apex S and base face ABCD such that the pyramid has an inscribed sphere (i.e., it contains a sphere which is tangent to each race). By making cuts along the edges SA,SB,SC,SD and rotating the faces SAB,SBC,SCD,SDA outwards into the plane ABCD, we unfold the pyramid into the polygon AKBLCMDN as shown in the figure. Prove that K,L,M,N are concyclic.

Tibor Bakos and Géza Kós
In a triangle ABC with a right angle at C, the angle bisector AL (where L is on segment BC) intersects the altitude CH at point K. The bisector of angle BCH intersects segment AB at point M. Prove that CK=ML
Alexey Doledenok
In convex pentagon ABCDE points A_1, B_1, C_1, D_1, E_1 are intersections of pairs of diagonals (BD, CE), (CE, DA), (DA, EB), (EB, AC) and (AC, BD) respectively. Prove that if four of quadrilaterals AB_{1}A_{1}B, BC_{1}B_{1}C, CD_{1}C_{1}D, DE_{1}D_{1}E and EA_{1}E_{1}A are cyclic then the fifth one is also cyclic.

Nairi Sedrakyan and Yuliy Tikhonov

Points P and Q are chosen on the side BC of triangle ABC so that P lies between B and Q. The rays AP and AQ divide the angle BAC into three equal parts. It is known that the triangle APQ is acute-angled. Denote by B_1,P_1,Q_1,C_1 the projections of points B,P,Q,C onto the lines AP,AQ,AP,AQ, respectively. Prove that lines B_1P_1 and C_1Q_1 meet on line BC.

Let ABCD be a tetrahedron and suppose that M is a point inside it such that \angle MAD=\angle MBC and \angle MDB=\angle MCA. Prove thatMA\cdot MB+MC\cdot MD<\max(AD\cdot BC,AC\cdot BD).

source: megapolis.educom.ru/en

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