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QEDMO 2005-12, 2015-17 (Germany) 35p (-13th)

  geometry problems from QEDMO, a German Math Flight  with aops links

aops post collections: QEDMO 
(inside zip)

a few words by  Darij Grinberg
QEDMO stands for QED Mathematical Olympiad. The QED is an organization of German mathematical olympiad participants based in Bavaria who organize meetings and seminars for each other. From late 2005 on, some of these meetings feature a math fight (an oral mathematical contest, with two teams solving questions and debating the solutions in front of the blackboard) called the QEDMO. The problems are of varying difficulty (some very basic problems occur on every QEDMO, but a few of the problems have the level of an IMO problem 3).  


Darij Grinberg was the one responsible for the selection of the geometry problems.

13/15 editions, 2005 - 2012, 2015-17 

 2003: 12th or 13th  only in aops here
 (I do not know if it is 12th or 13th)


2005 1st QEDMO p2 (G2) by Darij Grinberg
Let ABC be a triangle. Let C^{\prime} and A^{\prime} be the reflections of its vertices C and A, respectively, in the altitude of triangle ABC issuing from B. The perpendicular to the line BA^{\prime} through the point C^{\prime} intersects the line BC at U; the perpendicular to the line BC^{\prime} through the point A^{\prime} intersects the line BA at V. Prove that UV \parallel CA.

2005 1st QEDMO p5 (G1) by Darij Grinberg
Let ABC be a triangle, and let C^{\prime} and A^{\prime} be the feet of its altitudes issuing from the vertices C and A, respectively. Denote by P the midpoint of the segment C^{\prime}A^{\prime}. The circumcircles of triangles AC^{\prime}P and CA^{\prime}P have a common point apart from P; denote this common point by Q. Prove that:
(a) The point Q lies on the circumcircle of the triangle ABC.
(b) The line PQ passes through the point B.
(c) We have \frac{AQ}{CQ}=\frac{AB}{CB}.

2004 1st QEDMO p9 (G3) by Darij Grinberg
Let ABC be a triangle with AB\neq CB. Let C^{\prime} be a point on the ray [AB such that AC^{\prime}=CB. Let A^{\prime} be a point on the ray [CB such that CA^{\prime}=AB. Let the circumcircles of triangles ABA^{\prime} and CBC^{\prime} intersect at a point Q (apart from B). Prove that the line BQ bisects the segment CA.

2005 1st QEDMO p14 (G4) by Darij Grinberg
Let ABCDE be a convex pentagon. Let A^{\prime}=BD\cap CE, B^{\prime}=CE\cap DA, C^{\prime}=DA\cap EB, D^{\prime}=EB\cap AC and E^{\prime}=AC\cap BD. Furthermore, let A^{\prime\prime}=AA^{\prime}\cap EB, B^{\prime\prime}=BB^{\prime}\cap AC, C^{\prime\prime}=CC^{\prime}\cap BD, D^{\prime\prime}=DD^{\prime}\cap CE and E^{\prime\prime}=EE^{\prime}\cap DA.
Prove that:
\frac{EA^{\prime\prime}}{A^{\prime\prime}B}\cdot\frac{AB^{\prime\prime}}{B^{\prime\prime}C}\cdot\frac{BC^{\prime\prime}}{C^{\prime\prime}D}\cdot\frac{CD^{\prime\prime}}{D^{\prime\prime}E}\cdot\frac{DE^{\prime\prime}}{E^{\prime\prime}A}=1. 

2006 2nd QEDMO p4  by Darij Grinberg
Let ABCD be a cyclic quadrilateral. Let X be the foot of the perpendicular from the point A to the line BC, let Y be the foot of the perpendicular from the point B to the line AC, let Z be the foot of the perpendicular from the point A to the line CD, let W be the foot of the perpendicular from the point D to the line AC.
Prove that XY\parallel ZW.

2006 2nd QEDMO p7, by Darij Grinberg (combining other problems in one)
Let H be the orthocenter of a triangle ABC, and let D be the midpoint of the segment AH.
The altitude BH of triangle ABC intersects the perpendicular to the line AB through the point A at the point M. The altitude CH of triangle ABC intersects the perpendicular to the line CA through the point A at the point N. The perpendicular bisector of the segment AB intersects the perpendicular to the line BC through the point B at the point U.
The perpendicular bisector of the segment CA intersects the perpendicular to the line BC through the point C at the point V. Finally, let E be the midpoint of the side BC of triangle ABC.
Prove that the points D, M, N, U, V all lie on one and the same perpendicular to the line AE.

Extensions. In other words, we have to show that the points M, N, U, V lie on the perpendicular to the line AE through the point D. Additionally, one can find two more points on this perpendicular:

(a) The nine-point circle of triangle ABC is known to pass through the midpoint E of its side BC. Let D^{\prime} be the point where this nine-point circle intersects the line AE apart from E. Then, the point D^{\prime} lies on the perpendicular to the line AE through the point D.
(b) Let the tangent to the circumcircle of triangle ABC at the point A intersect the line BC at a point X. Then, the point X lies on the perpendicular to the line AE through the point D.

(most parts of this problem are due to Victor Thebault, 1950, but got rediscovered by manyothers - e. g. part of this problem was in Balkan MO 2003)


2006 2nd QEDMO p10 by Darij Grinberg
Let X_1, Z_2, Y_1, X_2, Z_1, Y_2 be six points lying on the periphery of a circle (in this order). Let the chords Y_1Y_2 and Z_1Z_2 meet at a point A; let the chords Z_1Z_2 and X_1X_2 meet at a point B; let the chords X_1X_2 and Y_1Y_2 meet at a point C.
Prove that \left( BX_2-CX_1\right) \cdot BC+\left( CY_2-AY_1\right) \cdot CA+\left( AZ_2-BZ_1\right) \cdot AB=0.

2006 2nd QEDMO p14 (Moscow MO 2005)
On the sides BC, CA, AB of an acute-angled triangle ABC, we erect (outwardly) the squares BB_aC_aC, CC_bA_bA, AA_cB_cB, respectively. On the sides B_cB_a and C_aC_b of the triangles BB_cB_a and CC_aC_b, we erect (outwardly) the squares B_cB_vB_uB_a and C_aC_uC_vC_b.
Prove that B_uC_u\parallel BC

2006 3rd QEDMO p1  by Engel 
Peter is a pentacrat and spends his time drawing pentagrams.
With the abbreviation \left|XYZ\right| for the area of an arbitrary triangle XYZ, he notes that any convex pentagon ABCDE satisfies the equality
\left|EAC\right|\cdot\left|EBD\right|=\left|EAB\right|\cdot\left|ECD\right|+\left|EBC\right|\cdot\left|EDA\right|.
Guess what you are supposed to do and do it.
(P151 in the German periodical Praxis der Mathematik)

2006 3rd QEDMO p6 by Darij Grinberg
The incircle of a triangle ABC touches its sides BC, CA, AB at the points X, Y, Z, respectively. Let X^{\prime}, Y^{\prime}, Z^{\prime} be the reflections of these points X, Y, Z in the external angle bisectors of the angles CAB, ABC, BCA, respectively. Show that Y^{\prime}Z^{\prime}\parallel BC, Z^{\prime}X^{\prime}\parallel CA and X^{\prime}Y^{\prime}\parallel AB.

2006 3rd QEDMO p9 by Darij Grinberg
Let ABC be a triangle, and C^{\prime} and A^{\prime} the midpoints of its sides AB and BC. Consider two lines g and g^{\prime} which both pass through the vertex A and are symmetric to each other with respect to the angle bisector of the angle CAB. Further, let Y and Y^{\prime} be the orthogonal projections of the point B on these lines g and g^{\prime}.
Show that the points Y and Y^{\prime} are symmetric to each other with respect to the line C^{\prime}A^{\prime}.

2007 4th QEDMO p1 by V. Alekseev, V. Galkin, V. Panferov, V. Tarasov
Let ABCD be a trapezoid with BC\parallel AD, and let O be the point of intersection of its diagonals AC and BD. Prove that \left\vert ABCD\right\vert =\left(  \sqrt{\left\vert BOC\right\vert }+\sqrt{\left\vert DOA\right\vert }\right)  ^{2}.

(exercise 8 in: V. Alekseev, V. Galkin, V. Panferov, V. Tarasov, 
Zadachi o trapezijah, Kvant 6/2000, pages 37-4.)

Let ABC be a triangle, and let X, Y, Z be three points on the segments BC, CA, AB, respectively. Denote by X^{\prime}, Y^{\prime}, Z^{\prime} the reflections of these points X, Y, Z in the midpoints of the segments BC, CA, AB, respectively. Prove that \left\vert XYZ\right\vert =\left\vert X^{\prime}Y^{\prime}Z^{\prime}\right\vert.
(P144 in the German periodical Praxis der Mathematik)

2007 4th QEDMO p10 by John Sturgeon Mackay
Let ABC be a triangle. The A-excircle of triangle ABC has center O_{a} and touches the side BC at the point A_{a}. The B-excircle of triangle ABC touches its sidelines AB and BC at the points C_{b} and A_{b}. The C-excircle of triangle ABC touches its sidelines BC and CA at the points A_{c} and B_{c}.  The lines C_{b}A_{b} and A_{c}B_{c} intersect each other at some point X. Prove that the quadrilateral AO_{a}A_{a}X is a parallelogram.

(Theorem (88) in: John Sturgeon Mackay, The Triangle and its Six Scribed Circles, Proceedings of the Edinburgh Mathematical Society 1 (1883), pages 4-128 and drawings at the end of the volume.)

2007 4th QEDMO p12 by rohitsingh0812 in aops
Let ABC be a triangle, and let D, E, F be the points of contact of its incircle \omega with its sides BC, CA, AB, respectively. Let K be the point of intersection of the line AD with the incircle \omega different from D, and let M be the point of intersection of the line EF with the line perpendicular to AD passing through K. Prove that AM is parallel to BC.

2007 5th QEDMO p2 by Darij Grinberg
Let ABCD be a (not self-intersecting) quadrilateral satisfying \measuredangle DAB = \measuredangle BCD\neq 90^{\circ}. Let X and Y be the orthogonal projections of the point D on the lines AB and BC, and let Z and W be the orthogonal projections of the point B on the lines CD and DA.
Establish the following facts:
a) The quadrilateral XYZW is an isosceles trapezoid such that XY\parallel ZW.
b) Let M be the midpoint of the segment AC. Then, the lines XZ and YW pass through the point M.
c) Let N be the midpoint of the segment BD, and let X^{\prime}, Y^{\prime}, Z^{\prime}, W^{\prime} be the midpoints of the segments AB, BC, CD, DA. Then, the point M lies on the circumcircles of the triangles W^{\prime}X^{\prime}N and Y^{\prime}Z^{\prime}N.

2007 5th QEDMO p8 by Darij Grinberg
Let A, B, C, A^{\prime}, B^{\prime}, C^{\prime}, X, Y, Z, X^{\prime}, Y^{\prime}, Z^{\prime} and P be pairwise distinct points in space such that
A^{\prime} \in BC;\ B^{\prime}\in CA;\ C^{\prime}\in AB;\ X^{\prime}\in YZ;\ Y^{\prime}\in ZX;\ Z^{\prime}\in XY;
P \in AX;\ P\in BY;\ P\in CZ;\ P\in A^{\prime}X^{\prime};\ P\in B^{\prime}Y^{\prime};\ P\in C^{\prime}Z^{\prime}.
Prove that
\frac {BA^{\prime}}{A^{\prime}C}\cdot\frac {CB^{\prime}}{B^{\prime}A}\cdot\frac {AC^{\prime}}{C^{\prime}B} = \frac {YX^{\prime}}{X^{\prime}Z}\cdot\frac {ZY^{\prime}}{Y^{\prime}X}\cdot\frac {XZ^{\prime}}{Z^{\prime}Y}.

Let there be a finite number of straight lines in the plane, none of which are three in one point to cut.
Show that the intersections of these straight lines can be colored with 3 colors so that that no two
points of the same color are adjacent on any of the straight lines. (Two points of intersection are called
adjacent if they both lie on one of the finitely many straight lines and there is no other such intersection
on their connecting line.)

Let A, B, C, A', B', C' be six pairs of different points. Prove that the Circles BCA', CAB' and
ABC' have a common point, then the Circles B'C'A, C'A'B and A'B'C also share a common point. Note: For three pairs of different points X, Y and Z we define the Circle XYZ as the circumcircle
of the triangle XYZ, or - in the case when the points X, Y and Z lie on a straight line - this straight
line.
Albatross and Frankinfueter both own a circle. Frankinfueter also has stolen from Prof. Trugweg a ruler. Before that, Trugweg had two points with a distance of 1 drawn his (infinitely large) board. For a natural number n, let A (n) be the number of the construction steps that Albatross needs at least to create two points with a distance of n to construct. Similarly, Frankinfueter needs at least F(n) steps for this. How big can \frac{A (n)}{F (n)} become? There are only the following three construction steps: a) Mark an intersection of two straight lines, two circles or a straight line with one circle. b) Pierce at a marked point P and draw a circle around P through one marked point . c) Draw a straight line through two marked points (this implies possession of a ruler ahead!).
The inscribed circle of a triangle ABC has the center O and touches the triangle sides BC, CA and
AB at points X, Y and Z, respectively. The parallels to the straight lines ZX, XY and YZ the
straight lines BC, CA and AB (in this order!) intersect through the point O. Points K, L and M.
Then the parallels to the straight lines CA, AB and BC intersect through the points K, L and M
in one point.

Let ABCD and A'B'C'D' be two squares, both are oriented clockwise. In addition, it is assumed
that all points are arranged as shown in the figure.Then it has to be shown that the sum of the areas of
the quadrilaterals ABB'A' and CDD'C' equal to the sum of the areas of the quadrilaterals BCC'B'
and DAA'D'
Let ABC be a triangle. Let x_1 and x_2 be two congruent circles, which touch each other and
the segment BC, and which both lie within triangle ABC, and for which it also holds that x_1
touches the segment CA, and that x_2 is the segment AB. Let X be the contact point of these
two circles x_1 and x_2. Let y_1 and y_2 two congruent circles that touch each other and the
segment CA, and both within of triangle ABC, and for which it also holds that y_1 touches the
segment AB, and that y_2 the segment BC. Let Y be the contact point of these two circles
y_1 and y_2. Let z_1 and z_2 be two congruent circles that touch each other and the segment
AB, and both within triangle ABC, and for which it also holds that z_1 touches the segment
BC, and that z_2 the segment CA. Let Z be the contact point of these two circles z_1 and
z_2. Prove that the straight lines AX, BY and CZ intersect at a point. 2010 7th QEDMO p12
Let Y and Z be the feet of the altitudes of a triangle ABC drawn from angles B and C,
respectively. Let U and V be the feet of the perpendiculars from Y and Z on the straight line
BC. The straight lines $YV and ZU intersect at a point L. Prove that AL \perp BC$.

9 points are given in the interior of the unit square.
Prove there exists a triangle of area \le \frac18 whose vertices are three of the points

A synogon is a convex 2n-gon with all sides of the same length and all opposite sides are parallel. Show that every synogon can be broken down into a finite number of rhombuses.

Albatross and Frankinfueter are playing again: each of them takes turns choosing one point in the plane with integer coordinates and paint it in his favorite color. Albatross plays first. Someone wins as soon as there is a square with all four corners in the are colored in their own color. Does anyone has a winning strategy and if so, who?

Let P be a convex polygon, so have all interior angles smaller than 180^o, and let X be a point in the interior of P. Prove that P has a side [AB] such that the perpendicular from X to the line AB lies on the side [AB].

Find for which natural numbers n one can color the sides and diagonals of a regular n-gon with n colors in such a way that for each triplet in pairs of different colors, a triangle can be found, the sides of which are sides or diagonals of n-gon and which is colored with exactly these three colors.

Let n be a natural number and L = Z^2 the set of points on the plane with integer coordinates. Every point in L is colored now in one of the colors red or green. Show that there are n different points x_1,...,x_n \in L all of which have the same color and whose center of gravity is also in L and is of the same color.

In the following, a rhombus is one with edge length 1 and interior angles 60^o and 120^o . Now let n be a natural number and H a regular hexagon with edge length n, which is covered with rhombuses without overlapping has been. The rhombuses then appear in three different orientations. Prove that whatever the overlap looks exactly, each of these three orientations can be viewed at the same time.

Prove that there are 2012 points in the plane, none of which are three on one straight line and in pairs have integer distances .

soon 12th and 13th

Let D be a regular dodecagon in the plane. How many squares are there in the plane at least two vertices in common with the vertices of D?

Let ABC be a triangle of area 1 with medians s_a, s_b,s_c. Show that there is a triangle whose sides are the same length as s_a, s_b, and s_c, and determine its area.
Let \ell be a straight line and P \notin \ell be a point in the plane. On \ell are, in this arrangement, points A_1, A_2,... such that the radii of the incircles of all triangles P A_iA_{i + 1} are equal. Let k \in N. Show that the radius of the incircle of the triangle P A_j A_{j + k} does not depend on the choice of j \in N .


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