geometry problems from Silk Roal Mathematics Competitions (SRMC)
with aops links in the names
with aops links in the names
collected inside aops here
2002 - 2022
2002 Silk Road P1Let \triangle ABC be a triangle with incircle \omega(I,r)and circumcircle \zeta(O,R).Let l_{a} be the angle bisector of \angle BAC.Denote P=l_{a}\cap\zeta.Let D be the point of tangency \omega with [BC].Denote Q=PD\cap\zeta.Show that PI=QI if PD=r.
2003 Silk Road P2
Let s=\frac{AB+BC+AC}{2} be half-perimeter of triangle ABC. Let L and Nbe a point's on ray's AB and CB, for which AL=CN=s. Let K is point, symmetric of point B by circumcenter of ABC. Prove, that perpendicular from K to NL passes through incenter of ABC.
2004 Silk Road P3
In-circle of ABC with center I touch AB and AC at P and Q respectively. BI and CI intersect PQ at K and L respectively. Prove, that circumcircle of ILK touch incircle of ABC iff |AB|+|AC|=3|BC|
2005 Silk Road P3
Assume A,B,C are three collinear points that B \in [AC]. Suppose AA' and BB' are to parrallel lines that A', B' and C are not collinear. Suppose O_1 is circumcenter of circle passing through A, A' and C. Also O_2 is circumcenter of circle passing through B, B' and C. If area of A'CB' is equal to area of O_1CO_2, then find all possible values for \angle CAA'
2007 Silk Road P2
Let \omega be the incircle of triangle ABC touches BC at point K . Draw a circle passing through points B and C , and touching \omega at the point S . Prove that S K passes through the center of the exscribed circle of triangle A B C , tangent to side B C .
2008 Silk Road P2
Let ABC be a triangle and A_0,B_0,C_0 be the midpoints of BC,CA,AB,respectively.And A_1,B_1,C_1 be the midpoints of broken lines BAC, ABC, ACB,respectively.Prove that A_0A_1,B_0B_1,C_0C_1 are concurrent.
2009 Silk Road P2
Bisectors of triangle ABC of an angles A and C intersect with BC and AB at points A_1 and C_1 respectively. Lines AA_1 and CC_1 intersect circumcircle of triangle ABC at points A_2 and C_2 respectively. K is intersection point of C_1A_2 and A_1C_2. I is incenter of ABC. Prove that the line KI divides AC into two equal parts.
2010 Silk Road P1
In a convex quadrilateral it is known ABCD that \angle ADB + \angle ACB = \angle CAB + \angle DBA = 30^{\circ} and AD = BC. Prove that from the lengths DB, CA and DC, you can make a right triangle.
2011 Silk Road P2
Given an isosceles triangle ABC with base AB. Point K is taken on the extenstion of the side AC (beyond the point C ) so that \angle KBC = \angle ABC. Denote S the intersection point of angle - bisectors of \angle BKC and \angle ACB. Lines AB and KS intersect at point L, lines BS and CL intersect at point M . Prove that line KM passes through the middle of the segment BC.
2012 Silk Road P1
Trapezium ABCD, where BC||AD, is inscribed in a circle, E is middle of the arc AD of this circle not containing point C . Let F be the base of the perpendicular dropped from E on the line tangent to the circle at the point C . Prove that BC=2CF.
2013 Silk Road P2
Circle with center I, inscribed in a triangle ABC , touches the sides BC and AC at points A_1 and B_1 respectively. On rays A_1I and B_1I, respectively, let be the points A_2 and B_2 such that IA_2=IB_2=R, where Ris the radius of the circumscribed circle of the triangle ABC. Prove that:
a) AA_2 = BB_2 = OI where O is the center of the circumscribed circle of the triangle ABC,
b) lines AA_2 and BB_2 intersect on the circumcircle of the triangle ABC.
2014 Silk Road P2
Let w be the circumcircle of non-isosceles acute triangle ABC. Tangent lines to w in A and B intersect at point S. Let M be the midpoint of AB, and H be the orthocenter of triangle ABC. The line HA intersects lines CM and CS at points M_a and S_a, respectively. The points M_b and S_b are defined analogously. Prove that M_aS_b and M_bS_a are the altitudes of triangle M_aM_bH.
2015 Silk Road P4
Let O be a circumcenter of an acute-angled triangle ABC. Consider two circles \omega and \Omega inscribed in the angle BAC in such way that ω is tangent from the outside to the arc BOC of a circle circumscribed about the triangle BOC, and the circle \Omega is tangent internally to a circumcircle of triangle ABC. Prove that the radius of \Omega is twice the radius \omega.
2016 Silk Road P2
Around the acute-angled triangle ABC (AC>CB) a circle is circumscribed, and the point N is midpoint of the arc ACB of this circle. Let the points A_1 and B_1 be the bases of perpendiculars on the straight line NC, drawn from points A and B respectively (segment NC lies inside the segment A_1B_1). Altitude A_1A_2 of triangle A_1AC and altitude B_1B_2 of triangle B_1BC intersect at a point K . Prove that \angle A_1KN=\angle B_1KM, where M is midpoint of the segment A_2B_2 .
2017 Silk Road P2
Quadrilateral ABCD inscribed in a circle \omega. Diagonals AC and BD intersect at a point O. On segments AO and DO points E and F are selected respectively. Straight EF crosses \omega in points E_{1} and F_{1}. The circumscribed circles of triangles ADE and BCF cross the segment EF in points E_{2} and F_{2} respectively (assume that all points E, E_{1}, E_{2}, F, F_{1}, F_{2} are different). Prove that E_{1}E_{2}=F_{1}F_{2}
2018 Silk Road P1
In an acute-angled triangle ABC on the sides AB, BC, AC the points H, L, K so that CH \perp AB, HL \parallel AC, HK \parallel BC. Let P and Q feet of altitudes of a triangle HBL, drawn from the vertices H and B respectively. Prove that the feet of the altitudes of the triangle AKH, drawn from the vertices A and H lie on the line PQ.
2019 Silk Road P1
The altitudes of the acute-angled non-isosceles triangle ABC intersect at the point H . On the segment C_1H , where CC_1 is the altitude of the triangle, the point K is marked. Points L and M are the bases of perpendiculars from point K to straight lines AC and BC , respectively. The lines AM and BL intersect at N . Prove that \angle ANK = \angle HNL .
2020 Silk Road P2
The triangle ABC is inscribed in the circle \omega . Points K, L, M are marked on the sides AB, BC, CA , respectively, and CM \cdot CL = AM \cdot BL . Ray LK intersects line AC at point P . The common chord of the circle \omega and the circumscribed circle of the triangle KMP meets the segment AM at the point S . Prove that SK \parallel BC .
In a triangle ABC, M is the midpoint of the AB. A point B_1 is marked on AC such that CB=CB_1. Circle \omega and \omega_1, the circumcircles of triangles ABC and BMB_1, respectively, intersect again at K. Let Q be the midpoint of the arc ACB on \omega. Let B_1Q and BC intersect at E. Prove that KC bisects B_1E.
Convex quadrilateral ABCD is inscribed in circle w.Rays AB and DC intersect at K.\ L is chosen on the diagonal BD so that \angle BAC= \angle DAL.\ M is chosen on the segment KL so that CM \mid\mid BD. Prove that line BM touches w.
source: http://matol.kz/nodes/93
No comments:
Post a Comment