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Zhautykov 2005-22 (IZhO) (Kazakhstan) 37p

geometry problems from International Zhautykov Olympiad (also known as IZhO)

2005 - 2022

IZhO 2005  Junior 5
Let the circle (I, r) be inscribed in the triangle ABC. Let D be the point of contact of this circle with BC. Let E and F be the midpoints of BC and AD, respectively. Prove that the three points I, E, F are collinear.

IZhO 2005  Senior 2
Let {SABC}. be a regular triangular pyramid (SA=SB=SC. and AB=BC=CA). Find the locus of all points {D \, (D\ne S)}. in the space that satisfy the equation { |cos \delta_A -2cos \delta_B - 2cos \delta_C | = 3 }. where the angle {\delta_X=\angle XSD} for each {X \in \{ A,B,C\} }.

The inner point X of a quadrilateral is observable from the side YZ if the perpendicular to the line Y Z meet it in the closed interval [Y Z]. The inner point of a quadrilateral is a k−point if it is observable from the exactly k sides of the quadrilateral. Prove that if a convex quadrilateral has a 1-point then it has a k − point for each k = 2, 3, 4.

Let ABC be a triangle and K and L be two points on (AB), (AC) such that BK = CL and let P = CK \cap  BL. Let the parallel through P to the interior angle bisector of ÐBAC intersect AC in M. Prove that CM = AB.

Let ABCDEF be a convex hexagon such that AD = BC + EF, BE = AF + CD, CF = DE + AB. Prove that: AB / DE = CD / AF = EF / BC .

Let ABCD be a convex quadrilateral, with ÐBAC = ÐDAC and M a point inside such that ÐMBA = ÐMCD and ÐMBC = ÐMDC. Show that the angle ÐADC is equal to ÐBMC or ÐAMB.

Let ABCDEF be a convex hexagon and it‘s diagonals have one common point M. It is known that the circumcenters of triangles MAB, MBC, MCD, MDE, MEF, MFA lie on a circle. Show that the quadrilaterals ABDE, BCEF, CDFA have equal areas.

Points K,L,M,N are respectively the midpoints of sides AB,BC,CD,DA in a convex quadrilateral ABCD. Line KM meets diagonals AC and BD at points P and Q, respectively .Line LN meets diagonals AC and BD at points R and S, respectively. Prove that if AP·PC = BQ·QD, then AR·RC = BS·SD.

Let A1A2 be the external tangent line to the nonintersecting circles ω1(O1) and ω2(O2), A1ω1,  A2ω2. Points K is the midpoint of A1A2. And KB1 and KB2 are tangent lines to ω1 and ω2, respectively (B1 ≠ A1, B2 ≠ A2).Lines A1B1 and A2B2 meet in point L, and lines KL and O1O2 meet in point P. Prove that points B1,B2, P and L are concyclic.

For a convex hexagon ABCDEF with an area S, prove that:
AC·(BD+BF − DF)+CE·(BD+DF −BF)+AE·(BF +DF − BD) ≥ 2√3 S

Given a quadrilateral ABCD with ÐB = ÐD = 90o. Point M is chosen on segment AB so that AD=AM. Rays DM and CB intersect at point N. Points H and K are feet of perpendiculars from points D and C to lines AC and AN, respectively. Prove that ÐMHN = ÐMCK.

In a cyclic quadrilateral ABCD with AB = AD points M,N lie on the sides BC and CD respectively so that MN = BM +DN . Lines AM and AN meet the circumcircle of ABCD again at points P and Q respectively. Prove that the orthocenter of the triangle APQ lies on the segment MN .

Let ABC arbitrary triangle (AB ≠ BC ≠AC ≠AB) and O,I,H it’s circumcenter, incenter and orthocenter . Prove, that
1) ÐOIH  >  90o
2) ÐOIH > 135 o

Given is trapezoid ABCD, M and N being the midpoints of the bases of AD and BC, respectively.
a) Prove that the trapezoid is isosceles if it is known that the intersection point of perpendicular bisectors of the lateral sides belongs to the segment MN.
b) Does the statement of part a) remain true if it is only known that the intersection point of perpendicular bisectors of the lateral sides belongs to the line MN?

Diagonals of a cyclic quadrilateral ABCD intersect at point K. The midpoints of diagonals AC and BD are M and N, respectively. The circumscribed circles ADM and BCM intersect at points M and L. Prove that the points K,L,M, and N lie on a circle. (all points are supposed to be different.)

An acute triangle ABC is given. Let D be an arbitrary inner point of the side AB. Let M and N be the feet of the perpendiculars from D to BC and AC, respectively. Let H1 and H2 be the orthocenters of triangles MNC and MND, respectively. Prove that the area of the quadrilateral AH1BH2 does not depend on the position of D on AB.

Equilateral triangles ACBand BDCare drawn on the diagonals of a convex quadrilateral ABCD so that B and Bare on the same side of AC, and C and Care on the same sides of BD. Find ÐBAD + ÐCDA if BC= AB + CD.

Given a trapezoid ABCD (AD // BC) with ÐABC > 90. Point M is chosen on the lateral side AB. Let O1 and O2 be the circumcenters of the triangles MAD and MBC, respectively. The circumcircles of the triangles MO1D and MO2C meet again at the point N. Prove that the line O1O2 passes through the point N.

Given convex hexagon ABCDEF with AB // DE, BC // EF, and CD // FA . The distance between the lines AB and DE is equal to the distance between the lines BC and EF and to the distance between the lines CD and FA. Prove that the sum AD+BE+CF does not exceed the perimeter of hexagon ABCDEF.

Points M, N, K lie on the sides BC, CA, AB of a triangle ABC, respectively, and are different from its vertices. The triangle MNK is called beautiful if ÐBAC = ÐKMN and ÐABC = ÐKNM. If in the triangle ABC there are two beautiful triangles with a common vertex, prove that the triangle ABC is right-angled.
 (Nairi M. Sedrakyan, Armenia)

Four segments divide a convex quadrilateral into nine quadrilaterals. The points of intersections of these segments lie on the diagonals of the quadrilateral (see figure). It is known that the quadrilaterals 1, 2, 3, 4 admit inscribed circles. Prove that the quadrilateral 5 also has an inscribed circle.

(Nairi M. Sedrakyan, Armenia)
Inside the triangle ABC a point M is given. The line BM meets the side AC at N. The point K is symmetrical to M with respect to AC. The line BK meets AC at P. If ÐAMP = ÐCMN, prove that ÐABP = ÐCBN.

(Nairi M. Sedrakyan, Armenia)
The area of a convex pentagon ABCDE is S, and the circumradii of the triangles ABC, BCD, CDE, DEA, EAB are R1, R2, R3, R4, R5. Prove the inequality
R_{1}^{4}+R_{2}^{4}+R_{3}^{4}+R_{4}^{4}+R_{5}^{4}\ge \frac{4}{5{{\sin }^{2}}{{108}^{o}}}{{S}^{2}}

(Nairi M. Sedrakyan, Armenia)
A quadrilateral ABCD is inscribed in a circle with center O. It’s diagonals meet at M. The circumcircle of ABM intersects the sides AD and BC at N and K respectively. Prove that areas of NOMD and KOMC are equal.

 (Sava Grozdev) 
A convex hexagon ABCDEF is given such that AB||DE, BC||EF, CD||FA. The point M,N,K are common points of the lines BD and AE, AC and DF, CE and BF respectively. Prove that perpendiculars drawn from M,N,K to lines AB,CD,EF respectively concurrent.

(Nairi M. Sedrakyan, Armenia)
Let ABC be a non-isosceles triangle with circumcircle ω and let H,M be orthocenter and midpoint of AB respectively. Let P,Q be points on the arc AB of ω not containing C such that ÐACP = ÐBCQ  <  ÐACQ. Let R, S be the foot of altitudes from H to CQ,CP respectively. Prove that the points P,Q,R, S are concyclic and M is the center of this circle.

(M. Kungojin
Let ABCD be the regular tetrahedron, and M,N points in space. Prove that:
AM · AN + BM · BN + CM · CN ≥ DM · DN

(Nairi M. Sedrakyan, Armenia)
IZhO 2018.2
Let N,K,L be points on AB,BC,CA such that CN bisector of angle \angle ACB and AL=BK.Let BL\cap AK=P.If I,J be incenters of triangles \triangle BPK and \triangle ALP and IJ\cap CN=Q prove that IQ=JP


In a circle with a radius R a convex hexagon is inscribed. The diagonals AD and BE,BE and CF,CF and AD of the hexagon intersect at the points M,N andK, respectively. Let r_1,r_2,r_3,r_4,r_5,r_6 be the radii of circles inscribed in triangles ABM,BCN,CDK,DEM,EFN,AFK respectively. Prove that.r_1+r_2+r_3+r_4+r_5+r_6\leq R\sqrt{3} .


Triangle ABC is given. The median CM intersects the circumference of ABC in N. P and Q are chosen on the rays CA and CB respectively, such that PM is parallel to BN and QM is parallel to AN. Points X and Y are chosen on the segments PM and QM respectively, such that both PY and QX touch the circumference of ABC. Let Z be intersection of PY and QX. Prove that, the quadrilateral MXZY is circumscribed.


Triangle ABC with AC=BC given and point D is chosen on the side AC. S1 is a circle that touches AD and extensions of AB and BD with radius R and center O_1. S2 is a circle that touches CD and extensions of BC and BD with radius 2R and center O_2. Let F be intersection of the extension of AB and tangent at O_2 to circumference of BO_1O_2. Prove that FO_1=O_1O_2.

Given convex hexagon ABCDEF, inscribed in the circle. Prove that AC*BD*DE*CE*EA*FB \geq 27 AB * BC * CD * DE * EF * FA

In a scalene triangle ABC I is the incentr and CN is the bisector of angle C. The line CN meets the circumcircle of ABC again at M. The line l is parallel to AB and touches the incircle of ABC. The point R on l is such. That CI \bot IR. The circumcircle of MNR meets the line IR again at S. Prpve that AS=BS.

In a convex cyclic hexagon ABCDEF, BC=EF and CD=AF. Diagonals AC and BF intersect at point Q, and diagonals EC and DF intersect at point P. Points R and S are marked on the segments DF and BF respectively so that FR=PD and BQ=FS. The segments RQ and PS intersect at point T. Prove that the line TC bisects the diagonal DB.

Let there be an incircle of triangle ABC, and 3 circles each inscribed between incircle and angles of ABCLet r, r_1, r_2, r_3 be radii of these circles (r_1, r_2, r_3 < r). Prove thatr_1+r_2+r_3 \geq r

A ten-level 2-tree is drawn in the plane: a vertex A_1 is marked, it is connected by segments with two vertices B_1 and B_2, each of B_1 and B_2 is connected by segments with two of the four vertices C_1, C_2, C_3, C_4 (each C_i is connected with one B_j exactly); and so on, up to 512 vertices J_1, \ldots, J_{512}. Each of the vertices J_1, \ldots, J_{512} is coloured blue or golden. Consider all permutations f of the vertices of this tree, such that (i) if X and Y are connected with a segment, then so are f(X) and f(Y), and (ii) if X is coloured, then f(X) has the same colour. Find the maximum M such that there are at least M permutations with these properties, regardless of the colouring.

In triangle ABC, a point M is the midpoint of AB, and a point I is the incentre. Point A_1 is the reflection of A in BI, and B_1 is the reflection of B in AI. Let N be the midpoint of A_1B_1. Prove that IN > IM.


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